Bernoulli differential equations are ordinary differential equations in the form
- $ \frac{dy}{dx}+P(x)y=Q(x)y^n $
If $ n=0 $ or $ n=1 $ then it is linear. Otherwise it is non-linear, although they can be transformed into a first order linear differential equation by means of a substitution
- $ z=y^{1-n} $
This will then reduce the equation (after some manipulation and simplification) to a first order linear ODE which can be solved with an integrating factor.
For example:
- $ \frac{dy}{dx}-2x^{-1}y=-x^2y^2 $
- $ y^{-2}\frac{dy}{dx}-2x^{-1}y^{-1}=-x^2 $
Now we can make the substitution
- $ w=y^{-1},\frac{dw}{dx}=-y^{-2}\frac{dy}{dx} $
This will give us:
- $ \frac{dw}{dx}+2x^{-1}w=x^2 $
This can now be solved the same way as a linear equation. The final answer is
- $ y=\frac{5x^2}{x^5+C} $
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